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Saturday, September 28, 2013

SV#1 Unit: F Concept: 10: Given polynomial of 4th or 5th degree, find all zeroes (real of complex zeroes)

This video demonstrates an example problem on finding zeroes of a polynomial of 4th degree. We list out all possible real/rational zeroes (p's and q's). Then we use Descarte's Rule of Signs to find out how many possible positive and negative real zeroes there will be. We use the Factor Theorem and start trying to find remainders of zero (zero heroes) using a number from the p/q list. Continue to find zero heroes until your reduce your polynomial to a quadratic. Once you have a quadratic, factor it using the quadratic formula.

Remember to take out a GCF from your quadratic before using the values inside the parenthesis into your quadratic equation. Break down your square root (if you can) and in your remaining factors you should distribute the GCF if there are any fractions.

Monday, September 16, 2013

SP#2: Unit E Concept 7- Graphing polynomials, including x-intercept, y-intercept, zeroes, (with multiplicities), end behavior


This problem is about graphing polynomials using its x-intercept, y-intercept, zeroes (with multiplicities), and end behavior. Factoring the equation will help you find the zeroes that will help you graph the points of the equation on the graph. It's end behavior allows you to know the direction of the arrows and then you graph the y-intercept.

Pay special attention to the multiplicity of the zeroes so you know how to act around the x-axis! A multiplicity of 1(T) will go straight through the graph, 2 (B) will bounce off the graph; does not cross the x-axis, and 3 (C) will curve through the graph.

Monday, September 9, 2013

SP#1: Unit E Concept 1- Identifying x-intercepts, y-intercepts, vertex (max,min), axis of quadratics, and graphing them

In this problem, in order to graph the equation more easily we complete the square in standard form to put it in parent function form: a(x-h)^2+k. Our graph includes 4 points: the vertex, y-intercept, axis and x-intercepts.

Pay attention to the max and min of the vertex so in our case it is min because the "a" in the equation is positive. Note that when solving for your x-intercepts you may end up with two,one or none (imaginary) x-intercepts so when you have your x-intercept, plug it into a calculator you have your exact and approximate x-intercepts.