Remember to take out a GCF from your quadratic before using the values inside the parenthesis into your quadratic equation. Break down your square root (if you can) and in your remaining factors you should distribute the GCF if there are any fractions.
Saturday, September 28, 2013
SV#1 Unit: F Concept: 10: Given polynomial of 4th or 5th degree, find all zeroes (real of complex zeroes)
Remember to take out a GCF from your quadratic before using the values inside the parenthesis into your quadratic equation. Break down your square root (if you can) and in your remaining factors you should distribute the GCF if there are any fractions.
Monday, September 16, 2013
SP#2: Unit E Concept 7- Graphing polynomials, including x-intercept, y-intercept, zeroes, (with multiplicities), end behavior
This problem is about graphing polynomials using its x-intercept, y-intercept, zeroes (with multiplicities), and end behavior. Factoring the equation will help you find the zeroes that will help you graph the points of the equation on the graph. It's end behavior allows you to know the direction of the arrows and then you graph the y-intercept.
Pay special attention to the multiplicity of the zeroes so you know how to act around the x-axis! A multiplicity of 1(T) will go straight through the graph, 2 (B) will bounce off the graph; does not cross the x-axis, and 3 (C) will curve through the graph.
Wednesday, September 11, 2013
Tuesday, September 10, 2013
Monday, September 9, 2013
SP#1: Unit E Concept 1- Identifying x-intercepts, y-intercepts, vertex (max,min), axis of quadratics, and graphing them
In this problem, in order to graph the equation more easily we complete the square in standard form to put it in parent function form: a(x-h)^2+k. Our graph includes 4 points: the vertex, y-intercept, axis and x-intercepts.
Pay attention to the max and min of the vertex so in our case it is min because the "a" in the equation is positive. Note that when solving for your x-intercepts you may end up with two,one or none (imaginary) x-intercepts so when you have your x-intercept, plug it into a calculator you have your exact and approximate x-intercepts.
Pay attention to the max and min of the vertex so in our case it is min because the "a" in the equation is positive. Note that when solving for your x-intercepts you may end up with two,one or none (imaginary) x-intercepts so when you have your x-intercept, plug it into a calculator you have your exact and approximate x-intercepts.
Monday, September 2, 2013
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